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Question 125

Find the values of x and y in the given figure.



Solution


In ΔTQS, T+Q+S=180    [angle sum property of a triangle]
50+30+1=18080+1=1801=18080=100
Now, 1+x=180       [linear pair]
100+x=180x=180100x=80
In ΔTSR,x+45+2=180     [angle sum property of a triangle]
2=1808045=55
Now, 50+2+y=180       [linear pair]
y=1805055=75


Mathematics
NCERT Exemplar
Standard VII

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