Find the values of x and ysuch that 32x1y9 is divisible by 11?
A
6 and 2
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B
2 and 7
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C
1 and 6
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D
4 and 2
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Solution
The correct option is B2 and 7 We know the divisibility rule for 11: If the difference of the sum of its digits at odd places and sum of its digits at even places is either 0 or a number divisible by 11.
322179: Sum of the odd places =3+2+7=12 Sum of the even places =2+1+9=12 Difference = Sum of the odd places − Sum of the even places Difference =12−12=0 So, 322179 is divisible by 11. Hence, the value of x and y is 2 and 7.