CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the values of x+y in the given rectangle.

81113_78a62c76310a4af992d7bd0f42d5f70d.jpg

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5
The given figure is a rectangle.
Therefore, the opposite sides are equal.
x+3y=13 .....(1)
and 3x+y=7 ....(2)
Subtracting (2) from the product (1) ×3, we get
8y=32
y=4
Putting this value in equation (1), we get
x+3(4)=13
x+12=13
x=1
Therefore, x+y=4+1=5.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon