Question

# Find the volume strength of 0.8N H2O2 solution.

A
4.48 V
B
0.8 V
C
0.4 V
D
2.5 V

Solution

## The correct option is A 4.48 VBy definition, volume strength is the amount of O2 (g)  in L produced by 1 L of H2O2 on decomposition H2O2 (aq)Δ⟶H2O (l)+0.5 O2 (g) nf=2 Normality=Molarity×n-factor Molarity=0.82 M=0.4 M This means 0.4 moles of H2O2 are present in 1L of solution. From the above reaction 1 mol H2O2 produces 0.5×22.4 L=11.2 L of O2 (g) at STP 0.4 mol H2O2 produces (0.4×11.2) L=4.48 L of O2 (g) at STP ∴ volume strength is 4.48 V Theory :  Volume strength of H2O2 : Decomposition of H2O2 : 2H2O2(aq)Δ⟶2H2O(l)+O2(g) The concentration of H2O2 is usually represented in terms of volume (V). If a sample of H2O2 is labelled as ‘x V’, it means that 1 vol. of H2O2 solution gives x vol of O2 gas at STP on complete decomposition We know that H2O2 decomposes as : H2O2(aq)⟶H2O(l)+0.5O2(g) Volume Strength of H2O2 = N×5.6=M×11.2 Alternate solution: Volume strength=Normality×5.6Volume strength=0.8×5.6=4.48  Chemistry

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