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Question

Find the volume strength of 0.8N H2O2 solution.


A
4.48 V
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B
0.8 V
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C
0.4 V
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D
2.5 V
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Solution

The correct option is A 4.48 V
By definition, volume strength is the amount of O2 (g)  in L produced by 1 L of H2O2 on decomposition
H2O2 (aq)ΔH2O (l)+0.5 O2 (g)
nf=2

Normality=Molarity×n-factor
Molarity=0.82 M=0.4 M
This means 0.4 moles of H2O2 are present in 1L of solution.
From the above reaction
1 mol H2O2 produces 0.5×22.4 L=11.2 L of O2 (g) at STP

0.4 mol H2O2 produces (0.4×11.2) L=4.48 L of O2 (g) at STP
volume strength is 4.48 V



Theory : 
Volume strength of H2O2 :
Decomposition of H2O2 :
2H2O2(aq)Δ2H2O(l)+O2(g)
The concentration of H2O2 is usually represented in terms of volume (V).
If a sample of H2O2 is labelled as ‘x V’, it means that 1 vol. of H2O2 solution gives x vol of O2 gas at STP on complete decomposition
We know that H2O2 decomposes as :
H2O2(aq)H2O(l)+0.5O2(g)
Volume Strength of H2O2 = N×5.6=M×11.2

Alternate solution:
Volume strength=Normality×5.6Volume strength=0.8×5.6=4.48
 

Chemistry

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