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Question

Find the wavelength associated with an electron which has mass $$9.1 \times {10}^{-28} g$$ and is moving with a velocity of $${10}^{5} cm$$ $${sec}^{-1}$$. (Given: $$h=6.625 \times {10}^{-27} erg-sec$$).


A
λ=5.28×105m.
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B
λ=7.28×105cm.
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C
λ=7.28×105m.
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D
λ=5.28×105cm.
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Solution

The correct option is B $$\lambda = 7.28 \times {10}^{-5} cm$$.
$$\because \lambda=\cfrac{h}{mv}$$
$$\therefore \lambda=\cfrac{6.625\times 10^{-27}}{9.1\times 10^{-28}\times 10^5}=7.28\times 10^{-5}cm$$
$$Note:$$ Units should be taken care of .

Chemistry

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