Question

# Find the wavelength associated with an electron which has mass $$9.1 \times {10}^{-28} g$$ and is moving with a velocity of $${10}^{5} cm$$ $${sec}^{-1}$$. (Given: $$h=6.625 \times {10}^{-27} erg-sec$$).

A
λ=5.28×105m.
B
λ=7.28×105cm.
C
λ=7.28×105m.
D
λ=5.28×105cm.

Solution

## The correct option is B $$\lambda = 7.28 \times {10}^{-5} cm$$.$$\because \lambda=\cfrac{h}{mv}$$$$\therefore \lambda=\cfrac{6.625\times 10^{-27}}{9.1\times 10^{-28}\times 10^5}=7.28\times 10^{-5}cm$$$$Note:$$ Units should be taken care of .Chemistry

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