Question

Find the zeros of the following polynomial

$p\left(x\right)=x^2+3x-4$

Answer 1

Since, $p\left(x\right)=x^2+3x-4=0$
$\Rightarrow x^2+4x-x4=0$
$\Rightarrow (x+)(x-1)=0$
$\Rightarrow x+4=0andx-1=0$
$\Rightarrow x=-4andx=1$