Find three consecutive terms in an A.P. whose sum is −3 and the product of their cubes is 512.
Let the numbers be (a−d),a,(a+d). Then,
Product of their cubes=512⇒(a−d)3×a3×(a+d)3=512
If d=3, then the numbers are −4,−1,2. If d=−3, then the numbers are 2,−1,−4.