Find total number of stereoisomers for each compound given below.
$P h - O | | S - C H = C H - C H_{2} - C H = C = C = C H - C H = C H - C H_{3}$

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $8$
Number of stereoisomers= $2^{n} ⟶$ For unsymmetrical molecule
$n$ = number of stereogenic centre (asymmetric)
(Refer to Image)
Thus $n = 3$
Number of stereoisomers= $2^{n} = 2^{3} = 8$

Suggest Corrections

Similar questions

C H_{3} - C H = C H - C | B r H - C H_{3}

C H_{3} - C H = C = C H - C H = C H - C H = C = C H - C H_{3}

B r - C H = C H - C H_{2} - C H = C H - C H_{2} - C H = C = C = C H - C H = C (C H_{3})_{2}

C H_{3} - C H = C H - C H_{2} - O | | C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O | | C - O H

C l - C H = C H - C l | C | H - C H = C H - C l

Join BYJU'S Learning Program