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Question

 Find total number of stereoisomers for each compound given  below.
$$Ph-\overset{O}{\overset{||}S} -CH = CH - CH_2 - CH = C = C = CH - CH = CH - CH_3$$


A
16
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B
4
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C
8
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D
none
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Solution

The correct option is C $$8$$
Number of stereoisomers= $$2^n \longrightarrow$$ For unsymmetrical molecule
$$n$$= number of stereogenic centre (asymmetric)
(Refer to Image)
Thus $$n=3$$
Number of stereoisomers= $$2^n=2^3=8$$

1187138_988442_ans_1af76b47401b410cb8a502790f2496ee.JPG

Chemistry

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