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Question

Find two consective multiples of 3 whose product is 648. 


Solution

Let two consecutive multiples of 3 be x and (x+3)

A/q,

x×(x+3)= 648

➡ x² + 3x = 648 

➡ x² + 3x -648 = 0

➡ x² + 27x - 24x -648 = 0

➡ x ( x + 27 ) -24 ( x +27)

➡ ( x - 24) ( x + 27)

➡ x = 24 and x = -27

so, we take x = 24.

Required multiples of 3 

➡ x = 24

➡ x +3 = 24+3 = 27.
 


Mathematics
Secondary School Mathematics X
Standard X

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