Find two consecutive integers such that two-fifth of the smaller exceeds two-ninth of the greater by 4
I think u wanted to ask two consecutive odd integers not two consecutive Integers.because when I solved for two consecutive integers I assumed that the two numbers are x and x+1 but there exist no such numbers so I solved it for two consecutive odd integers.
let two consecutive nos be x and x+2
According to the question-
2x/5 = 2/9( x+2) + 4
2x/5 = 2x/9 + 4/9 + 4
2x/5 - 2x/9 = 40/9
(18x - 10x)/45 = 40/9
8x = 200
x = 200/8 = 25
Therefore the two consecutive positive odd no.s are 25 and 27.