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Question

Find two consecutive positive odd integers whose product is 483.


Solution

1st number = x
2nd number= x+2

so: x(x+2) = 483
x² + 2x -483= 0

making the factors of equation we get
x² + 23x - 21x -483= 0
(x-21) (x + 23)= 0
x= 21
x= -23(-ve value cannot consider)
so 1st no= 21
2nd no = 23

Mathematics
Secondary School Mathematics X
Standard X

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