Question

# Find two numbers such that the larger number added to three times the smaller number gives 7 and twice the larger number added to the smaller number gives 9.4, 7 2, 5 None of these 1, 4

Solution

## The correct option is D 1, 4 Let the larger number be x and the smaller number be y.                 x + 3y = 7                                             …(i)                 2x + y = 9                                             …(ii) On multiplying (i) by 2 and (ii) by 1, we get        2x+6y=14        2x+y=9 Solving the above two equations, we get 5y = 5 Or y = 55 = 1 On substituting value of y in (i), we get                 x + 3×1 = 7 or             x + 3 = 7 or             x = 7 – 3 = 4 ∴   Larger number is 4 and smaller number is 1.

Suggest corrections