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Question

Five particles of masses 2 kg each are attached to the circumference of circular disc of a radius 0.1m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is?

A
1 kg m2
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B
0.1kg m2
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C
2 kg m2
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D
0.2 kg m2
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Solution

The correct option is B 0.1kg m2

The moment of inertia of the given system that contains 5 particles each of mass = 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is given by .=momentofinertiaofdisc+momentofinertiaofparticle Since, the mass of the disc is negligible therefore, MI of the system = MI of particle =5×2×(0.1)2=0.1kgm2


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