Question

# Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacobs age was seven times that of his son. What are their present ages?

A
Jacob=80years,son=40years
B
Jacob=30years,son=10years
C
Jacob=40years,son=10years
D
Jacob=50years,son=20years

Solution

## The correct option is C $$Jacob =40years , son=10years$$$$Let\>the\>present\>age\>of\>Jacob\>=\>x\>years\\and\>that\>of\>his\>son\>=\>y\>years\\(x+5)=3(y+5)\\or\>x=3y+10\\$$$$and\>(x-5)=7(y-5)\\x-5=7y-35\\40=4y\\\therefore\>y=10\>years\>and\>then\>x\>=\>30+10=40\>years$$So, the correct option is 'Jacob $$= 40$$ years, son $$= 10$$ years'.Maths

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