Question

# Fluorine exhibits only -1 oxidation state while iodine exhibits oxidation states of -1, + 1, + 3, +5 and + 7. This is due to :

A
flourine being a gas
B
available d-orbitals in iodine
C
non-availability of d-orbitals in iodine
D
none of the above.

Solution

## The correct option is C available $$d$$-orbitals in iodineDue to absence of d-orbitals, $$F$$ can not expand its valency but $$I$$ can expand its valency (as shown in the figure) and therefore, exhibts variable oxidation states.Chemistry

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