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Question

Following four solutions are prepared by mixing different volumes of NaOH and HCl of different concentrations, pH of which one of them will be equal to $$1$$?


A
55mL M10HCl +45mL M10NaOH
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B
75mL M5HCl+25mL M5NaOH
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C
100mL M10HCl+100mL M10NaOH
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D
60mL M10HCl+40mL M10NaOH
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Solution

The correct option is C $$75$$mL $$\displaystyle\frac{M}{5}$$HCl$$+25$$mL $$\displaystyle\frac{M}{5}$$NaOH
$$75$$mL $$\displaystyle\frac{M}{5}$$HCl$$+25$$mL 

$$\displaystyle\frac{M}{5}$$NaOH
25mL $$\displaystyle\frac{M}{5}$$NaOH will neutralise 25 mL 

$$\displaystyle\frac{M}{5}$$HCl
$$75-25=50$$ mL $$\displaystyle\frac{M}{5}$$HCl will remain.
Total volume will be $$75+25=100$$ mL.
50 mL $$\displaystyle\frac{M}{5}$$HCl is diluted to 100 mL.
$$\displaystyle [H^+]=[HCl]=\frac{M}{5} \times \frac{50}{100}=\frac{M}{10}$$
$$\displaystyle pH=-log_{10}[H^+]=-log_{10}\frac{M}{10}=1$$

Chemistry

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