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Question

For 2rn, (nr)+2(nr1)+(nr2) is equal to
  1. (n+1r1)
  2. (n+1r+1)
  3. 2(n+2r)
  4. (n+2r)


Solution

The correct option is D (n+2r)
(nr)+2(nr1)+(nr2)=[(nr)+(nr1)]
[(nr1)+(nr2)]=(n+1r)+(n+1r1)=(n+2r)
[  nCr+nCr1=n+1Cr]

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