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Question

For a>b>c>0, the distance between (1,1) and the point of intersection of the lines ax+by+c=0 and bx+ay+c=0 is less then 22. Then

A
a+bc>0
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B
ab+c<0
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C
ab+c>0
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D
a+bc<0
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Solution

The correct option is A a+bc>0
The intersection point of two lines is (ca+b,ca+b)
Distance between (1,1) and (ca+b,ca+b)<22
2(1+ca+b)2<81+ca+b<2a+bc>0

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