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Question

For a body in S.H.M. the velocity is given by the relation $$ v = \sqrt{144-16x^{2}}\ m/s$$. The maximum acceleration is


A
12 m/s2
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B
16 m/s2
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C
36 m/s2
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D
48 m/s2
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Solution

The correct option is C $$48\ m/ s^{2} $$
$$v=\omega \sqrt{A^{2}-x^{2}}$$
Comparing $$\omega =4\dfrac{rad}{sec} ; A^{2}=9 ; A=3m$$
$$a= -\omega ^{2}A$$
$$=-16\times 3=-48 m/s^{2}$$

Physics

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