Question

# For a body in S.H.M. the velocity is given by the relation $$v = \sqrt{144-16x^{2}}\ m/s$$. The maximum acceleration is

A
12 m/s2
B
16 m/s2
C
36 m/s2
D
48 m/s2

Solution

## The correct option is C $$48\ m/ s^{2}$$$$v=\omega \sqrt{A^{2}-x^{2}}$$Comparing $$\omega =4\dfrac{rad}{sec} ; A^{2}=9 ; A=3m$$$$a= -\omega ^{2}A$$$$=-16\times 3=-48 m/s^{2}$$Physics

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