Question

For a broad gauge railway track on a horizontal curve of radius 'R' (in m) the equilibrium cant 'e' required for a train moving at a speed of V (in km per hour) is

• A. $e=1.676\frac{V^2}{R}$
• B. $e=0.60\frac{V^2}{R}$
• C. $e=1.315\frac{V^2}{R}$
• D. $e=0.80\frac{V^2}{R}$

Answer 1

The correct option is C $e=1.315\frac{V^2}{R}$

Equilibrium cant $=\frac{G{V}^2}{127R}$
V in kmph and R in m.
For B.G track G = 1.676
Cant $=\frac{1.676V^2}{127R}m$
$e=\frac{1.319V^2}{R}cm$

The unit of e is not specified in the question but option b is matching in cm units.