    Question

# For a CE transistor amplifier, the audio signal voltage across the collector resistance of $2k$ omega is $4V$. If the current amplification factor of the transistor is $100$ and the base resistance is $1k$ Omega, then the input signal voltage is

A

$10mV$

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B

$20mV$

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C

$30mV$

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D

$15mV$

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Solution

## The correct option is B $20mV$Step 1: GivenAmplification factor, $\frac{{I}_{\alpha }}{{I}_{\beta }}=100=\beta$Resistance of the base, ${R}_{B}=1000\Omega$Resistance of the collector, ${R}_{L}=2000\Omega$Voltage across the collector resistance, ${V}_{0}=4V$Step 2: Find the input signal voltageUsing the formula, $\frac{{V}_{0}}{{V}_{i}}=\beta \frac{{R}_{L}}{{R}_{B}}$$\frac{4}{{V}_{i}}=100×\frac{2000}{1000}\phantom{\rule{0ex}{0ex}}⇒{V}_{i}=0.02V\phantom{\rule{0ex}{0ex}}=20mV$Hence, option B is the correct option.  Suggest Corrections  0      Similar questions
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