Question

For a certain reaction, the activation energy is zero. What is the value of rate constant at 300 K, if $k=1.6\times {10}^6{s}^{-1}$ at 280 K.

• A. $1.6\times {10}^6{s}^{-1}$
• B. zero
• C. $\infty$
• D. $3.2\times {10}^{12}{s}^{-1}$

Answer 1

The correct option is A $1.6\times {10}^6{s}^{-1}$

Explanation:

$log\frac{k_2}{k_1}=\frac{E_a}{2.303R}\left[\frac{T_2-T_1}{T_1{T}_2}\right](\because E_a=0)$

$\therefore log\frac{k_2}{k_1}=0$ or $\frac{k_2}{k_1}=antilog\left(0\right)$

$\therefore \frac{k_2}{k_1}=1$ or $k_2=k_1=1.6\times {10}^6{s}^{-1}$