Question

For a first order reaction rate constant is $1\times {10}^{-5}{\sec }^{-1}$ having $E_a=1800kJ/mol$ . Then the value of $\ell nA$ at$T=600K$ is:-

• A. $151.7$
• B. $349.3$
• C. $24.7$
• D. $11.34$

Answer 1

The correct option is A $151.7$

acc. to arrhenius equation

$k=A{e}^{-Ea/RT}$

rate constant $1\times {10}^{-5}{sec}^{-1}$

$Ea=1800kJ/mol$

$\log k=\log A-\frac{Ea}{RT}$

$\log (1\times {10}^{-5})=\log A-\frac{Ea}{RT}$

$\log A=\log (1\times {10}^{-5})+\frac{1800}{1\times {10}^{-5}\times 600}=151.7$