Question

# For $$a\in R$$ (the set of all real numbers), $$a\neq -1$$. $$\lim _{ n\rightarrow \infty }{ \frac { \left( { 1 }^{ a }+{ 2 }^{ a }+......+{ n }^{ a } \right) }{ { \left( n+1 \right) }^{ a-1 }\left[ \left( na+1 \right) +\left( na+2 \right) +.......+\left( na+n \right) \right] } =\dfrac { 1 }{ 60 } }$$, then $$a=$$

A
5
B
7
C
152
D
172

Solution

## The correct options are B $$7$$ D $$-\dfrac {17}{2}$$Maths

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