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Byju's Answer
Standard XII
Mathematics
Orthogonal Trajectories
for a particl...
Question
for a particle moving in a xy plane,the coordinates vary with time as x=3t and y =4t+4.The equation of trajectory of the particle is
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Similar questions
Q.
position of a particle moving in x-y plane as function of time t is
2
^
t
i
+
4
t
2
^
j
. equation of trajectory of the particle is
Q.
A particle is moving in X-Y plane such that
v
x
=
4
+
4
t
and
v
y
=
4
t
.
If the initial position of the particle is (1, 2). Then the equation of trajectory will be
Q.
The coordinates of a particle at any time
t
is given by
x
= 4
t
– 3
t
2
and
y
= 3
t
. Equation of trajectory followed by particle is
किसी समय
t
पर एक कण के निर्देशांकों को
x
= 4
t
– 3
t
2
तथा
y
= 3
t
द्वारा व्यक्त किया जाता है। कण द्वारा अनुसरित प्रक्षेप-पथ की समीकरण है
Q.
A particle moves in x-y plane such that its position vector varies with time as
¯
r
= (2sin3t)
^
i
+2(1-cos3t)
^
j
. Find the equation of the trajectory of the particle.
Q.
The coordinates of a particle moving in x-y plane at any instant of time t are
x
=
4
t
2
;
y
=
3
t
2
. The speed of the particle at that instant is :
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