For a sample of perfect gas when its pressure is changed isothermally from $p_{i}$ to $p_{f},$ the entropy change is given by

Δ S = n R T l n (\frac{p_{f}}{p_{i}})

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Δ S = R T l n (\frac{p_{i}}{p_{f}})

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Δ S = n R l n (\frac{p_{f}}{p_{i}})

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Δ S = n R l n (\frac{p_{i}}{p_{f}})

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Solution

The correct option is D $Δ S = n R l n (\frac{p_{i}}{p_{f}})$
$Δ S = n C_{p, m} l n \frac{T_{f}}{T_{i}} + n R l n \frac{P_{i}}{P_{f}}$
For isothermal $T_{i} = T_{f} \Rightarrow l n 1 = 0$
$Δ S = n R l n \frac{P_{i}}{P_{f}}$

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The entropy change can be calculated by using the expression $Δ S = \frac{q_{r e v}}{T}$ .
When water freezes in a glass beaker, choose the correct statement amongst the following.
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(b) $Δ$ S (system) increases but $Δ$ S (surroundings) decreases
(c) $Δ$ S (system) decreases but $Δ$ S (surroundings) increases
(d) $Δ$ S (system) decreases but $Δ$ S (surroundings) also decreases

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For a sample of perfect gas when its pressure is changed isothermally from pi to pf, the entropy change is given by

The correct option is D ΔS=nR ln(pipf)ΔS=nCp,m lnTfTi+nR lnPiPf For isothermal Ti=Tf⇒ln 1=0 ΔS=nR lnPiPf

For a sample of perfect gas when its pressure is changed isothermally from $p_{i}$ to $p_{f},$ the entropy change is given by

The correct option is D $Δ S = n R l n (\frac{p_{i}}{p_{f}})$
$Δ S = n C_{p, m} l n \frac{T_{f}}{T_{i}} + n R l n \frac{P_{i}}{P_{f}}$
For isothermal $T_{i} = T_{f} \Rightarrow l n 1 = 0$
$Δ S = n R l n \frac{P_{i}}{P_{f}}$