For a solution containing a non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, then the number of moles of solvent in the solution is:

4

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3

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Solution

The correct option is A $4$
$\frac{Δ P}{P_{0}} = X_{s o l u t e}$

$X_{s o l u t e} = 0 \cdot 2$

$\frac{n_{s o l u t e}}{n_{t o t a l}} = 0 \cdot 2$

$n_{s o l u t e} = 0 \cdot 2 \times 5 m o l = 1 m o l$

Then $n_{s o l v e n t} = 5 - 1 = 4 m o l e s$

Hence, the correct option is $A$

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For a solution containing a non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, then the number of moles of solvent in the solution is:

The correct option is A 4ΔPP0=XsoluteXsolute=0⋅2nsolutentotal=0⋅2nsolute=0⋅2×5 mol=1 molThen nsolvent=5−1=4 molesHence, the correct option is A

The correct option is A $4$
$\frac{Δ P}{P_{0}} = X_{s o l u t e}$

$X_{s o l u t e} = 0 \cdot 2$

$\frac{n_{s o l u t e}}{n_{t o t a l}} = 0 \cdot 2$

$n_{s o l u t e} = 0 \cdot 2 \times 5 m o l = 1 m o l$

Then $n_{s o l v e n t} = 5 - 1 = 4 m o l e s$

Hence, the correct option is $A$