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Question

For a solution to form positive deviation,the solute-solvent interactions must be less than solute-solute and solvent-solvent interactions,making it easier for the molecules to escape in its pure form.still,why does the vapour pressure of the solution showing positive deviation increase compared to the pure form?


Solution

Positive deviations :
In these type of deviations,the partial vapour pressure of each component A and B of solution is higher than the vapour pressure calculated from Raoult's law,
For eg : Water and ethanol,chloroform and water.
In the case of positive deviation A-B interactions are weaker than those between A-A or B-B.This means that in such solutions molecules of A (or B) will find it easier to escape than in pure state.This will increase the vapour pressure and results in the positive deviation from Raoult's law

ΔHmin=+ve

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