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Question

For adsorption of a gas:


A

ฮ”H<0,ฮ”S<0

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B

ฮ”H<0,ฮ”S>0

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C

ฮ”H>0,ฮ”S>0

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D

ฮ”H=0,ฮ”S>0

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Solution

The correct option is A

ฮ”H<0,ฮ”S<0


Explanation for the correct options:

A) ฮ”H<0,ฮ”S<0

According to Thermodynamics, ฮ”G=ฮ”H-Tฮ”S

ฮ”H<0, As the residual forces on the surface decrease, this indicates that there is a decrease in surface energy which will appear in form of heat. Thus, adsorption is an exothermic process. ฮ”S<0 , when the gas particles are adsorbed on the surface, the movement of the particles is very difficult as the particles stick with the surface of the adsorbent. This leads to a decrease in the entropy of the gas particles. So, ฮ”S<0 is negative.

Explanation for the incorrect options:

B) ฮ”H<0,ฮ”S>0

As the entropy of adsorbed gas is positive ฮ”S>0 ,the gas will not be adsorbed on the surface.

C) ฮ”H>0,ฮ”S>0

Adsorption is an exothermic reaction as ฮ”H>0 the reaction becomes endothermic. As the entropy of adsorbed gas is positive ฮ”S>0 , the gas will not be adsorbed to the surface. Thus, the adsorption process will not take place.

D) ฮ”H=0,ฮ”S>0

In this ฮ”H=0, so heat will be absorbed on the surface. As the entropy of adsorbed gas is positive ฮ”S>0,the gas will not be adsorbed on the surface.

Hence option (A) is correct, ฮ”H<0,ฮ”S<0


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