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Question

For any two sets, prove that :

(i) A(AB)=A

(ii) A(AB)=A

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Solution

(i) A(AB)=(AA)(AB)

[ union is distributive overintersection ]

= A(AB) [AA=A]

= A [A(AB), as union of two sets is bigger than each of the individual sets]

Hence , A(AB)=A Proved.

(ii) A(AB)=(AA)(AB)

[ distributes over ]

= A(AB)[AA=A]

= A [using (i)]


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