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Question

For constructing ΔLMN exactly identical to ΔABC, choose from the options, the minimum measurements required.


A

LM, MN and LN

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B

MN and LN

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C

LM, MN, LN and MLN

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D

LM, MN, LN, MLN and MNL

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Solution

The correct option is B

MN and LN


The lengths of sides MN and LN are sufficient to construct a triangle identical to ΔABC.
Draw MN as the base and with NL as length draw an arc. Now we can draw a line perpendicular to MN, this interests the arc at L. Hence the ΔMNL is constructed using the lengths of a side and a hypotenuse.


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