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Question

For nϵN, the value of the definite integral nπ+V01+cos2x2dx where π2<V<π is

A
2n+1cosV
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B
2nsinV
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C
2n+2sinV
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D
2n+1sinV
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Solution

The correct option is C 2n+2sinV
Given, nx+v02cos2x2dx=nx+v0|cosx|dx
nx0|cosx|dx+nx+v0|cosx|dx
nn0|cosx|dx+v0|cosx|dx
2n+n/20cosxdxvn/2cosxdx=2n+2sinv

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