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Question

For equation (x25x+5)x2+4x60=1

A
Number of real value of x=4
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B
Number of real value of x=5
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C
Sum of real value of x=1
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D
Sum of real value of x=3
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Solution

The correct option is A Number of real value of x=4
(x25x+5)x2+4x60=1(1)log(x25x+5)x2+4x60=log1(takinglogonbothside)(x2+4x60)log(x25x+5)=0(sincelog1=0)so,(x2+4x60)=0(0r)log(x25x+5)=0for,(x2+4x60)=0b24ac=424.1.(60)=256>0xhas2distinctrealrootsalsofor,log(x25x+5)=0log(x25x+5)=log1(sincelog1=0)(x25x+5)=0b24ac=(5)24.1.4=9>0xhas2distinctrealrootsforequation(1),numberofrealvaluesofx=4

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