For how long should a force of 200 N, act on a stationary body of 20 kg, so that it acquires a velocity of 100 m/s.?

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Solution

Given:
Mass of the body =20 kg
initial velocity u=0 m/s
Final velocity v=100 m/s
Force F =100 N

Acceleration $a = \frac{F}{m} = \frac{100}{20} = 5 m / s^{2}$

$t = \frac{v - u}{a} = \frac{100 - 0}{5} = 20 S$

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For how long should a force of 200 N, act on a stationary body of 20 kg, so that it acquires a velocity of 100 m/s.?

Given:Mass of the body =20 kginitial velocity u=0 m/sFinal velocity v=100 m/sForce F =100 NAcceleration a=Fm=10020=5m/s2t=v−ua=100−05=20S

Given:
Mass of the body =20 kg
initial velocity u=0 m/s
Final velocity v=100 m/s
Force F =100 N

Acceleration $a = \frac{F}{m} = \frac{100}{20} = 5 m / s^{2}$

$t = \frac{v - u}{a} = \frac{100 - 0}{5} = 20 S$