Question

# For how many values of k does the following system of equations have at-least one solution?           x+y=1;        kx+y=3;                x+ky=5;

A

0

B

1

C

2

D

Infinitely many

Solution

## The correct option is D 11.We have Adding the second and third equations we get (k+1)(x+y)=8, and hence k+1=8. Thus , k=7. The valus of x=1/3, y=2/3 satisfy the equations if k=7. Hence the answer is B.

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