CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For hyperbola x2cos2αy2sin2α=1, which of the following remains constant with change in 'α'

A
Abscissae of vertices
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Abscissae of foci
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Eccentricity
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Directrix
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Abscissae of foci
Hyperbola is x2cos2αy2sin2α=1,
Coordinates of vertices are (±cosα,0), eccentricity of the hyperbola is e=1+sin2αcos2α=|secα|
Coordinates of foci are thus (±1,0),which are independent of α. Directrix is x=±cos2α

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon