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Question

For Molybdenum, the wavelength of  Kα line is 0.72 nm and of  Kβ line is 0.60 nm. From this information wavelength of Lα line in nm is 


Solution

EMEK=hc0.6 and ELEK=hc0.72
EMEL=hc(10.610.72)
EMEL=hcλ
1λ=10.610.72λ=0.6×0.720.12
λ=3.6 nm

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