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Question

For one mole of a Vander Waal’s gas when b = 0 and T = 300K, the PV vs. 1V plot is shown below. The value of the vander waal's constant ‘a’ (atm L2mol2)



A
1
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B
4.5
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C
1.5
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D
3
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Solution

The correct option is D 1.5
The vanderwaal's equation of state is
(P+n2aV2)(Vnb)=nRT
For one mole and when b = 0, the above equation condenses to
(P+n2aV2)V=RTPV=RTaV   . . . . .(i)
Equation (i) is a straight line equation between PV and 1V whose slope is '- a'. Equating with slope of the straight line given in the graph
a=20.121.632=1.5a=1.5

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