For solving each pair of equations, use the method of eliminations by equating coefficients:
3−(x−5)=y+2
2(x+y)=4−3y
3−(x−5)=y+22(x+y)=4−3y−x−y=−6x+y=6...(1)2x+5y=4...(2)
Multiplying equation no. (1) by 2.
From (1)
15(x−2)=14(1−y)
26x+3y+4=0
y=2x−6
y=0
41x+53y=135
53x+41y=147