Question

For the chemical equation given below, what is the amount of methane required to produce 72 g of water? CH4(g)+2O2(g)→CO2(g)+2H2O(l)

A

32 g

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B

44 g

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C

64 g

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D

16 g

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Solution

The correct options are A 32 g Mass of water (H2O) to be produced = 72 g. Gram molecular mass of a compound is the sum of gram atomic mass of all the constituent atoms. Gram molecular mass of water = 18 g No. of moles of H2O in 72 g = Mass of waterGram molecular mass of water = 7218=4 mole For 2 moles of H2O → 1 mole of methane is required So, for 4 moles of H2O → 2 moles of methane is required. Gram molecular mass of methane = 16 g The required amount of methane =2×16=32 g.

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