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Question

For the circle x2+y2+6x+8y=0, and the points P(3,6) and Q(4,2),
  1. Q lies inside and P lies outside the circle
  2. P lies inside and Q lies outside the circle
  3. P,Q lie outside the circle
  4. P,Q lie inside the circle


Solution

The correct option is B P lies inside and Q lies outside the circle
Given circle S:x2+y2+6x+8y=0
Now putting P(3,6) coordinates in the circle equation
S1:32+621848=21
S1<0
So the point P lies inside the circle.

Now putting Q(4,2) coordinates in the circle equation
S2:42+22+2416=28>0
S2>0
So the point Q lies outside the circle.

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