Question

# For the complex ion of $$[Co(NH_3)_6]^{3+}$$:(i) State the hybridisation of the complex.(ii) State the magnetic nature of the complex.

Solution

## In $$[Co(NH_3)_6]^{3+}$$ the oxidation state of cobalt is $$+3$$.Ammonia is a strong field ligand so  it pair up 4 unpaired electron and free up 2 $$3-d$$ orbitals. These $$3-d$$ orbitals are involved in hybridisation with one $$4S$$ and three $$4P$$ orbitals forming an inner orbital complex, so hybridisation of $$[Co(NH_3)_6]^{3+}$$ is $$d^2sp^3$$Since it has no unpaired electrons, $$[Co(NH_3)_6]^{3+}$$ is diamagnetic.Chemistry

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