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Question

For the complex ion of $$[Co(NH_3)_6]^{3+}$$:
(i) State the hybridisation of the complex.
(ii) State the magnetic nature of the complex.


Solution

In $$[Co(NH_3)_6]^{3+}$$ the oxidation state of cobalt is $$+3$$.Ammonia is a strong field ligand so  it pair up 4 unpaired electron and free up 2 $$3-d$$ orbitals. These $$3-d$$ orbitals are involved in hybridisation with one $$4S$$ and three $$4P$$ orbitals forming an inner orbital complex, so hybridisation of $$[Co(NH_3)_6]^{3+}$$ is $$d^2sp^3$$

Since it has no unpaired electrons, $$[Co(NH_3)_6]^{3+}$$ is diamagnetic.


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Chemistry

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