Question

# For the equilibrium N2O4⇌2NO2 in gaseous phase, NO2 is 50% of the total volume when equilibrium is set up. Hence percent of dissociation of N2O4 is:

A
50%
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B
25%
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C
66.66%
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D
33.33%
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Solution

## The correct option is B 33.33%At equilibrium, NO2 is 50% of total volume. The remaining 50% of total volume will be N2O4In other words, VNO2=VN2O4=Vtotal2Suppose we start with 100 L of N2O4 and x L of N2O4 dissociate to provide 2x L ofNO2.(100−x) L of N2O4 will remain at equilibrium.Total volume at equilibrium =(100−x)+2x=(100+x) L.At equilibrium, NO2 is 50% of total volume. 2x L=(100+x) L22x=(100+x)24x=(100+x)3x=100x=33.33Hence, out of 100 L of N2O4, 33.33 L dissociates to reach equilibrium.The degree of dissociation =x100×100=33.33100×100=33.33.

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