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Byju's Answer

Standard XII

Chemistry

Faraday's First Law

For the follo...

Question

For the following cell,
$Z n (s) | {Z n S O}_{4} (a q) ∥ {C u S O}_{4} (a q) | C u (s)$
When the concentration of ${Z n}^{2 +}$ is $10$ times the concentration of ${C u}^{2 +}$ , the expression for the $△ G$ (in $J {m o l}^{- 1}$ ) is: [ $F$ is Faraday constant; $R$ is gas constant; $T$ is temperature; $E$ (cell) $= 1.1 V$ ]

2.303 R T + 1.1 F

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2.303 R - 2.2 F

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1.1 F

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- 2.2 F

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Solution

The correct option is B $2.303 R - 2.2 F$
Overall reaction:
$Z n + {C u}^{2 +} (a q) \to {Z n}^{2 +} (a q) + C u$
we know that,
$E = E^{\circ} - \frac{R T}{n F} l n \frac{[{Z n}^{2 +}]}{[{C u}^{2 +}]}$
$∴ E = 1.1 - \frac{R T}{2 F} l n 10$
Now, $Δ G = - n F E$
Here $n = 2$
$∴ △ G = - 2 F [1.1 - \frac{R T}{2 F} l n 10]$
$= - 2.2 F + R T {l o g}_{10} 10 \times 2.303$
$∴ △ G = 2.303 R T - 2.2 F$

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Similar questions

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Z n (s) | Z n S O_{4} (a q) ∥ C u S O_{4} (a q) | C u (s)

, when the concentration of

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10

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, the expression for

△ G

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[

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When the concentration of

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For the following cell,Zn(s)|ZnSO4(aq)∥CuSO4(aq)|Cu(s)When the concentration of Zn2+ is 10 times the concentration of Cu2+, the expression for the △G (in Jmol−1) is: [F is Faraday constant; R is gas constant; T is temperature; E(cell)=1.1V]

The correct option is B 2.303R−2.2FOverall reaction:Zn+Cu2+(aq)→Zn2+(aq)+Cuwe know that,E=E∘−RTnFln[Zn2+][Cu2+]∴E=1.1−RT2Fln10Now, ΔG=−nFEHere n=2∴△G=−2F[1.1−RT2Fln10] =−2.2F+RTlog1010×2.303∴△G=2.303RT−2.2F