The correct option is D lines intersect at point (3,0,−3)
Given lines:
L1:→r=2^i+^j−2^k+λ(^i−^j−^k)=→a+λ→b and L2:→r=^i−^j−2^k+μ(−2^i−^j+^k)=→c+μ→d
As →b is not parallel to →d
So, lines are either intersecting or skew.
Now any parametric point on L1=(2+λ,1−λ,−2−λ) and on L2=(1−2μ,−1−μ,−2+μ)
For point of intersection : L1=L2
⇒2+λ=1−2μ⋯(i)1−λ=−1−μ⋯(ii)−2−λ=−2+μ⋯(iii)
Solving (i) and (ii) we get, λ=1,μ=−1
which also satisfies equation (iii)
So, point of intersection is (3,0,−3)