For the given reaction PCl3(g)+Cl2(g)⇌PCl5(g)
If 2.0 mol of PCl5(g) is placed in a 2 L vessel at 300 K and 0.8 mole of PCl5(g) dissociated, what will be the equilibrium constant(Kc) of the reaction?
A
0.266
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B
0.366
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C
0.466
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D
3.75
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Solution
The correct option is D 3.75 Given reaction is PCl5(g)⇌PCl3(g)+Cl2(g)