    Question

# For the given situation, choose the correct option. A
At t=15 s, the acceleration of 2 kg block is 11 ms2.
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B
At t=1 s, the force of friction between 2 kg and 4 kg blocks is 2 N.
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C
At t=4 s, the force of friction between the ground and 4 kg block is 18 N.
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D
At t=1 s, the force of friction between 2 kg and 4 kg blocks is zero.
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Solution

## The correct option is D At t=1 s, the force of friction between 2 kg and 4 kg blocks is zero. Let f1→ frictional force between 2 kg and 4 kg Let f2→ frictional force between 4 kg and ground [fs]1max=0.4×2×10=8 N fk1=0.2×2×10=4 N [fs]2max=0.6×6×10=36 N fk2=0.4×6×10=24 N At t=1 s,F=2 N<36 N. System is stationary & frictional force between 2 kg and 4 kg is zero. At t=4 s,F=8 N<36 N. So, the system is stationary. The force of friction between ground and 4 kg is 8 N. At t=15 s,F=30 N<36 N. So, the system is stationary.  Suggest Corrections  0      Similar questions  Related Videos   Warming Up: Playing with Friction
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