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Question

For the principal quantum number n = 4, the total number of different possible values of the azimuthal quantum number $$l$$, is :


A
2
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B
8
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C
4
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D
3
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Solution

The correct option is C $$4$$
The principal quantum number is given as $$n = 4$$

Thus the azimuthal quantum number has values, $$l  =  0   \space  to  \space   (n-1)$$.

$$\therefore       l = 0,  1,  2 $$ and  $$3 $$               

$$\implies $$ Number of different values of  $$l$$ is $$4$$.

Hence, option $$C$$ is correct.

Chemistry

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