Question

# For the principal quantum number n = 4, the total number of different possible values of the azimuthal quantum number $$l$$, is :

A
2
B
8
C
4
D
3

Solution

## The correct option is C $$4$$The principal quantum number is given as $$n = 4$$Thus the azimuthal quantum number has values, $$l = 0 \space to \space (n-1)$$.$$\therefore l = 0, 1, 2$$ and  $$3$$               $$\implies$$ Number of different values of  $$l$$ is $$4$$.Hence, option $$C$$ is correct.Chemistry

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