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Question

For the reaction 2A + B + C A2B + C the rate law is found to be Rate =k[A][B]2 with k=2×106mol2L2s1
The initial rate of reaction with [A]=0.1molL1,[B]=0.2molL1 and [C]=0.8molL1 is

A
6.4×108molL1s1
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B
4×103molL1s1
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C
8×109molL1s1
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D
4×107molL1s1
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Solution

The correct option is C 8×109molL1s1
Rate=k[A][B]2=(2×106)(0.1)(0.2)2=8×109


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