For the reaction, 2H2(g)+2NO(g)→N2(g)+2H2O(g) The observed rate expression is, rate =kf[NO]2[H2]. The rate expression for the reverse reaction is:
A
kb[N2][H2O]2
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B
kb[N2][H2O]
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C
kb[N2][H2O]2[H2]
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D
kb[N2][H2O]2[NO]
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Solution
The correct option is Ckb[N2][H2O]2[H2] The reverse reaction is: 2H2(g)+2NO(g)⇌N2(g)+2H2O(g) The equilibrium constant, Kc=kfkb=[N2][H2O]2[H2]2[NO]2 At equilibrium, rate of forward reaction=rate of backward reaction